Probability of selecting one card from a standard deck
Three-part: a simple count for face cards, another simple count for red cards, then the addition rule for face-or-red with the six-card overlap correction.
A short walkthrough explaining what you need to know and how to solve this question type lands here once it's recorded.
ALEKS randomizes the numbers each attempt, but the question shape stays the same. Here are three example versions you might see.
Suppose one card is drawn at random from a standard deck of 52 cards. Find:
(a) P(face card)
(b) P(red card)
(c) P(face card OR red card)
Write each answer as a fraction.
One card is drawn from a 52-card deck. Find P(king), P(spade), and P(king or spade). Write each as a fraction in lowest terms.
One card is drawn from a 52-card deck. Find P(ace), P(heart), and P(ace or heart). Write each as a fraction in lowest terms.
subtract the overlap once so it isn't counted twice
(a) P(face card).
Face cards are J, Q, K in each of 4 suits: 3 × 4 = 12 face cards.
(b) P(red card).
Hearts and diamonds are red: 2 suits × 13 cards = 26 red cards.
(c) P(face OR red) — addition rule.
Identify the overlap: cards that are both face AND red are the J/Q/K of hearts and diamonds — 6 cards. So P(face AND red) = 6/52.
= 32/52 = 8/13
Try the king-or-spade variant. Same recipe: count each set, count the overlap (just one card here), apply the rule.
P(king or spade).
You've walked through the whole problem.
That's the move. ALEKS will give you a different version with different numbers — but the steps are the same.